5.4 Inverse trigonometric functions
Sine, cosine, and tangent are restricted to intervals on which they are one-to-one before inverse functions are defined.
5.4.1 Principal values and solving angles
Inverse sine. The function \(\arcsin:[-1,1]\to[-\pi/2,\pi/2]\) satisfying \(\sin(\arcsin x)=x\).
Inverse cosine has range \([0,\pi]\), while inverse tangent has range \((-\pi/2,\pi/2)\). A calculator returns only a principal value. When solving over a larger interval, use reference angles and quadrant signs to find all solutions.
Worked Example: Evaluating an inverse function
\(\arcsin(1/2)=\pi/6\), while \(\arcsin(-1/2)=-\pi/6\), because both lie in the principal range.
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\(3\pi/4\).Worked Example: Finding all angles in one revolution
If \(\cos\theta=-0.2250\) for \(0\le\theta<360^\circ\), the reference angle is approximately \(77.0^\circ\). Cosine is negative in quadrants II and III, so \(\theta\approx103.0^\circ\) or \(257.0^\circ\).
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\(\theta\approx36.87^\circ\) or \(143.13^\circ\).Worked Example: Evaluating a composition exactly
If \(\alpha=\arcsin(9/11)\), then a right triangle gives adjacent side \(\sqrt{40}\) and hypotenuse 11. Therefore,
\[\cos(\arcsin(9/11))=\frac{2\sqrt{10}}{11}.\]
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\(4/3\).Worked Example: Finding a channel angle
A channel rises 1.2 m over 18 m horizontally. Its inclination is
\[\theta=\arctan(1.2/18)\approx3.81^\circ.\]
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\(\arctan(0.9/25)\approx2.06^\circ\).Check Your Work
The reference angle is \(\arcsin(0.35)\approx20.5^\circ\). Sine is negative in quadrants III and IV, giving \(200.5^\circ\) and \(339.5^\circ\).5.4.2 Practice Problems
- Evaluate \(\arcsin(0)\).
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0. - Evaluate \(\arccos(1/2)\).
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\(\pi/3\). - Evaluate \(\arctan(1)\).
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\(\pi/4\). - Solve \(\cos\theta=0.4\) on \(0\le\theta<360^\circ\).
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\(\theta\approx66.4^\circ,293.6^\circ\). - Evaluate \(\sin(\arccos(5/13))\).
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\(12/13\). - A 2.5 m rise occurs over 40 m. Find the slope angle.
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\(\arctan(2.5/40)\approx3.58^\circ\). - A tank roof rises 3 m over a half-span of 8 m. Find its angle.
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\(\arctan(3/8)\approx20.6^\circ\). - A force has vertical component 45 N and magnitude 120 N. Find possible directions in one revolution.
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\(\sin\theta=0.375\), giving approximately \(22.0^\circ\) and \(158.0^\circ\).