2.7 Combining Functions
2.7.1 Learning Objectives
By the end of this section, you should be able to:
- add, subtract, multiply, and divide functions;
- determine the domain of a combined function;
- calculate and interpret a composition of functions;
- determine the domain of a composite function; and
- decompose a composite function into simpler functions.
2.7.2 Arithmetic Combinations of Functions
Functions can be combined using ordinary arithmetic:
\[ \begin{aligned} (f+g)(x)&=f(x)+g(x),\\ (f-g)(x)&=f(x)-g(x),\\ (fg)(x)&=f(x)g(x),\\ \left(\frac{f}{g}\right)(x)&=\frac{f(x)}{g(x)},\qquad g(x)\ne0. \end{aligned} \]
Example 2.33 Combining Two Functions
Let \(f(x)=x^2+1\) and \(g(x)=3x-2\). Find \(f+g\), \(fg\), and \(f/g\).
Solution
\[ \begin{aligned} (f+g)(x)&=x^2+3x-1,\\ (fg)(x)&=(x^2+1)(3x-2),\\ \left(\frac{f}{g}\right)(x)&=\frac{x^2+1}{3x-2},\qquad x\ne\frac23. \end{aligned} \]
\[ \boxed{(f+g)(x)=x^2+3x-1,\quad (fg)(x)=(x^2+1)(3x-2),\quad \left(\frac fg\right)(x)=\frac{x^2+1}{3x-2}} \]
Exercise 2.32 If \(f(x)=2x+5\) and \(g(x)=x-4\), find \((f-g)(x)\).
Show answer
Answer: \(\boxed{(f-g)(x)=x+9}\)
2.7.3 Domains of Combined Functions
For sums, differences, and products, use inputs common to the domains of both functions. For a quotient, also exclude inputs that make the denominator zero.
Example 2.34 Finding a Quotient’s Domain
Let \(f(x)=\sqrt{x+1}\) and \(g(x)=x-3\). Find the domain of \(f/g\).
Solution
The square root requires \(x\ge-1\), and the denominator requires \(x\ne3\). Thus,
\[ \boxed{[-1,3)\cup(3,\infty)}. \]
Exercise 2.33 Find the domain of \(\dfrac{\sqrt{x-2}}{x-5}\).
Show answer
Answer: \(\boxed{[2,5)\cup(5,\infty)}\)
2.7.4 Composition of Functions
The composition of \(f\) with \(g\) is
\[ (f\circ g)(x)=f(g(x)). \]
Apply the inner function first. In general, \(f\circ g\) and \(g\circ f\) are different.
Example 2.35 Comparing Two Compositions
For \(f(x)=x^2+1\) and \(g(x)=3x-2\), find \(f\circ g\) and \(g\circ f\).
Solution
\[ \begin{aligned} (f\circ g)(x)&=(3x-2)^2+1=9x^2-12x+5,\\ (g\circ f)(x)&=3(x^2+1)-2=3x^2+1. \end{aligned} \]
\[ \boxed{(f\circ g)(x)=9x^2-12x+5,\quad (g\circ f)(x)=3x^2+1} \]
Exercise 2.34 If \(f(x)=\sqrt{x}\) and \(g(x)=x+6\), find \((f\circ g)(x)\).
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Answer: \(\boxed{(f\circ g)(x)=\sqrt{x+6}}\)
2.7.5 Domains of Composite Functions
For \(f\circ g\), an input \(x\) must be in the domain of \(g\), and the output \(g(x)\) must be in the domain of \(f\).
Example 2.36 Restricting a Composite Domain
Let \(f(x)=\sqrt{x}\) and \(g(x)=x-4\). Find \(f\circ g\) and its domain.
Solution
\[ (f\circ g)(x)=\sqrt{x-4}. \]
The radicand must be non-negative:
\[ x-4\ge0. \]
Therefore,
\[ \boxed{(f\circ g)(x)=\sqrt{x-4},\quad \text{domain }[4,\infty)}. \]
Exercise 2.35 Let \(f(x)=1/x\) and \(g(x)=x^2-9\). Find the domain of \(f\circ g\).
Show answer
Answer: \(\boxed{(-\infty,-3)\cup(-3,3)\cup(3,\infty)}\)
2.7.6 Decomposing a Composition
A complicated expression can often be viewed as an outer function applied to an inner function. This helps reveal its structure.
Example 2.37 Identifying Inner and Outer Functions
Express \(H(x)=\sqrt{5x+1}\) as \(f\circ g\).
Solution
Choose the inner function \(g(x)=5x+1\) and the outer function \(f(u)=\sqrt{u}\). Then
\[ f(g(x))=\sqrt{5x+1}. \]
\[ \boxed{f(u)=\sqrt u,\quad g(x)=5x+1} \]
Exercise 2.36 Express \(H(x)=(2x-3)^4\) as \(f\circ g\).
Show answer
Answer: One choice is \(\boxed{g(x)=2x-3,\quad f(u)=u^4}\).
2.7.7 Applications and Iteration
Composition describes processes performed in sequence. Repeated composition of a function with itself is called iteration. The notation \(f^2(x)\) may mean \(f(f(x))\) in this context; it does not mean \([f(x)]^2\).
Example 2.38 Converting and Applying a Rate
The function \(C(F)=\frac59(F-32)\) converts Fahrenheit to Celsius. A second function \(W(C)=C-2\) models a wind adjustment. Find \(W(C(68))\).
Solution
\[ C(68)=\frac59(68-32)=20, \]
and
\[ W(20)=18. \]
\[ \boxed{W(C(68))=18^\circ\text{C}} \]
Exercise 2.37 If \(f(x)=0.5x+3\), calculate \(f(f(10))\).
Show answer
Answer: \(f(10)=8\), so \(f(f(10))=f(8)=\boxed{7}\).
2.7.8 Conceptual Takeaways
- Arithmetic combinations operate on the outputs of functions at the same input.
- The domain of a combination must respect every restriction in the original functions.
- Composition applies one complete function and then uses its output as the next input.
- The order of composition matters.
- Decomposition and iteration reveal how multi-stage processes are organized.
2.7.9 Skills You Should Be Able to Do
- Calculate sums, differences, products, and quotients of functions.
- Determine the domain of an arithmetic combination.
- Evaluate and simplify composite functions.
- Determine the domain of a composition.
- Decompose and interpret multi-stage functions.
2.7.10 Practice Problems with Solutions
Let \(f(x)=x+2\) and \(g(x)=x^2\). Find \((f+g)(x)\).
Show Solution
\[ (f+g)(x)=x+2+x^2. \]
Thus, \(\boxed{x^2+x+2}\).
For the functions in Problem 1, find \((fg)(-2)\).
Show Solution
\(f(-2)=0\) and \(g(-2)=4\), so
\[ \boxed{(fg)(-2)=0(4)=0}. \]
Find the domain of \(\dfrac{\sqrt{x+4}}{x-1}\).
Show Solution
The square root requires \(x\ge-4\), and the denominator requires \(x\ne1\). Hence,
\[ \boxed{[-4,1)\cup(1,\infty)}. \]
If \(f(x)=2x-1\) and \(g(x)=x^2+3\), find \((f\circ g)(x)\).
Show Solution
\[ f(g(x))=2(x^2+3)-1=2x^2+5. \]
Thus, \(\boxed{(f\circ g)(x)=2x^2+5}\).
For the functions in Problem 4, find \((g\circ f)(x)\).
Show Solution
\[ g(f(x))=(2x-1)^2+3=4x^2-4x+4. \]
Thus, \(\boxed{(g\circ f)(x)=4x^2-4x+4}\).
Let \(f(x)=\sqrt{x+1}\) and \(g(x)=2x-5\). Find \(f\circ g\) and its domain.
Show Solution
\[ (f\circ g)(x)=\sqrt{(2x-5)+1}=\sqrt{2x-4}. \]
The radicand requires \(2x-4\ge0\), so
\[ \boxed{(f\circ g)(x)=\sqrt{2x-4},\quad \text{domain }[2,\infty)}. \]
Decompose \(H(x)=\dfrac{1}{(x+4)^2}\) as \(f\circ g\).
Show Solution
Let \(g(x)=(x+4)^2\) and \(f(u)=1/u\). Then \(f(g(x))=1/(x+4)^2\).
\[ \boxed{g(x)=(x+4)^2,\quad f(u)=\frac1u} \]
A price \(p\) is increased by \(8\%\), then a \(\$5\) delivery fee is added. Write the final cost as a composition and find the cost when \(p=\$75\).
Show Solution
Let \(I(p)=1.08p\) apply the increase and \(D(x)=x+5\) add delivery. Then
\[ (D\circ I)(p)=1.08p+5. \]
For \(p=75\),
\[ (D\circ I)(75)=1.08(75)+5=86. \]
Therefore, \(\boxed{\$86}\).